The velocity in ft/sec of a particle is given by v(t) = −14t + 2. Find the position function s(t), of the particle if it has an initial position s(0) = 4 feet. A. 7t2 + 2t − 4
B. −7t2 + 2t + 4
C. −7t2 + 2t − 4
D. −14t2 + 2t + 4

mx+89b(-98)nb

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)