A new car is purchased for 16000 dollars. The value of the car depreciates at 6.25% per year. To the nearest tenth of a year, how long will it be until the value of the car is
11500 dollars?

5.1 years

Step-by-step explanation:

the formula for fixed rate depreciation is

Value after t years = initial value ( 1 - r )^t

where r = depreciation rate = 6.25% = 0.0625

t = length of time in years (we are asked to find this

Value after t years = given as $11,500

initial Value = given as $16,000

Substituting this into equation

11,500 = 16,000 (1 - 0.0625) ^t

11,500 = 16,000 (0.9375) ^t  (divide both sides by 16,000 and rearrange)

0.9375^t = 11,500 / 16000

0.9375^t = 0.71875  (taking log of both sides)

t log 0.9375 = log 0.71875

t =   log 0.71875 / log 0.9375  (use calculator)

t = 5.12

t = 5.1 years (nearest tenth)

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation: