In a certain breed of cattle, the length of gestation has a mean of 284 days and a standard deviation is 5.5 days. What length of gestation, rounded to the nearest whole number, represents the 18th percentile?
Find the Z-table here.
0 279 days
O 282 days
285 days
289 days

(m+11n)^2=(m+11n)(m+11n)=m^2+11mn+11mn+121n^2=m^2+22mn×121n^2 for example; use foil: (a+b)(a+b)first. a^2outside. abinside. ablast. b^2

The answer is a. yes, it asks a question that can be answered correctly (by measuring hands).

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60