What is an equation of the line that is perpendicular to y- 3 = -4(x + 2) and passes through the point (-5, 7)?
O A. y-7=-4(x + 5)
O B. y+7--(-5)
O C. y-7-1(x+5)
O D. y+ 7 = 4(x - 5)
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Step-by-step explanation:

First of a line perpendicular to another line has the inverse opposite slope

    if  m is the slope  m of line 1  the perpendicular line slope is   -1/m

y - 3 = -4(x + 2)    equarion 1

y - 3 = -4x - 8       -4 × (x+2)

y = -4x - 5            added 3 to both sides to get the y intercept form y=mx+b

the slope of the perpendicular line will be   1/4

using the point slope method

y - y1 = m(x -x1)    

the gives the (x,y) point of the perpendicular as (-5, 7)

x1 = -5

y1 = 7

y - 7 = 1/4(x - (-5))

y - 7 = 1/4(x +5)     <--------------   Answer

the attached graph shows the line and the perpendicular going through point (-5, 7)

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what is your question that you ask

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fwms@lil_ben06

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