The data set represents a progression of hourly temperature measurements. Use a graphing calculator to determine the quadratic regression equation for this data set
O 1 2 3
5
у 20 16 10 0 -7 -20
X
4
ay-0.795x2 + 3 796% + 20.130
b. y -0.7957-3760% + 20.120
C. y -0.8757 -3.9962 + 20.179
dy-0.7957 - 3.7962 * 20.120

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

the answer is  

a.

28 ft2

step-by-step explanation:

the equation is going to be

answer: i also need

step-by-step explanation: