Clark was trying to find the area of the figure below by splitting the shape into parallelograms and triangles. Is his method correct? .
A=(7x0.5) + (2x2) + (2.4 x 2.5) + (2.4 x 1.5).
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A=3.5 + 4 + 6 + 3.6
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A=17.1 square in.​

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.