Mathematics, 10.03.2021 17:20 issagirl23
Hello! :) please give an explanation for what is wrong and what should be done to fix this issue.![\frac{\sqrt[3]{64} }{\sqrt{64} } = \sqrt[3]{\frac{64}{64} } =1](/tpl/images/2214/0406/a1d08.png)
Answers: 1
![\sqrt[n]{ \frac{y}{x} } < = \frac{ \sqrt[n]{y} }{ \sqrt[n]{x} }](/tpl/images/1183/8375/60563.png)
let's solve:it's wrong because it doesn't follow the redical formula. it took one cube root and another square root which is wrong. both should be cube root According to the formula![\sf simplify \: roots : \\ \tt = \frac{ \sqrt[3]{64} }{ \sqrt{64} } \\ = \frac{4}{8} \\ = \frac{1}{2}](/tpl/images/1183/8375/7a152.png)
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Hello! :) please give an explanation for what is wrong and what should be done to fix this issue....
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