What equation represents a line in point slope form that has a slope of 5 and passes the point 1,6

Explanation is in the file

https://cutt.ly/kzjInUL

y = 5x+1

Step-by-step explanation:

y= mx+c --- The formula for a straight line

Substituting the slope:

y = 5x+c

Substituting x and y from the point:

6 = 5 + c

c = 6 - 5

c = 1

Hence,

y = 5x + 1

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°