Mathematics, 10.03.2021 07:30 3peak101

Write x^2 - 6x + 7 = 0 in the form (x - a)^2 = b, where a and b are integers. (x - 4)^2= 3
(x - 3)^2 = 2
(x - 2)^2 = 1
(x - 1)^2 = 4

Answers: 2

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Write x^2 - 6x + 7 = 0 in the form (x - a)^2 = b, where a and b are integers. (x - 4)^2= 3
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Write x^2 - 6x + 7 = 0 in the form (x - a)^2 = b, where a and b are integers. (x - 4)^2= 3 (x - 3)^2 = 2 (x - 2)^2 = 1 (x - 1)^2 = 4

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Another question on Mathematics

Write x^2 - 6x + 7 = 0 in the form (x - a)^2 = b, where a and b are integers. (x - 4)^2= 3
(x - 3)^2 = 2
(x - 2)^2 = 1
(x - 1)^2 = 4