A 10-foot ladder touches the side of a building at a point 8 feet above the ground. At what height would a 22-foot ladder touch the building if it makes the same angle with the ground as the shorter ladder? Round to the nearest tenth if necessary.

8.75 feet

Given that a 12 foot ladder leans against a building seven feet above the ground.

By using trigonometry ratio, the angle between the ladder and the ground will be

SinØ = opposite/ hypothenus

SinØ = 7 / 12

SinØ = 0.58333

Ø = Sin^-1(0.58333)

Ø = 35.69 degree

At what height would an 15 foot ladder touch the building if both ladders form the same angle with the ground?

Using the same trigonometric ratios

SinØ = opposite/hypothenus

Sin 35.69 = opposite/ 15

Cross multiply

Opposite = 15 × sin 35.69

Opposite = 8.75 feet

Therefore, the ladder will touch the building if both ladders form the same angle with the ground at height 8.75 feet.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

3/5

step-by-step explanation:

double number line is not a standard concept, so it must have been defined in your textbook. assume top line is numerator.