Using algebra, find the point at which the line k(x)=4x+12 intersects the line f(x)=1x+3

(-3, 0)

Step-by-step explanation:

We are given two linear functions:

And we want to find the point at which the two lines intersect.

At the point the two lines intersect, their y-values will be the same. In other words, we can set their functions equal to each other and solve for x. Thus:

Substitute:

Solve for x. Subtracting x from both sides yields:

And subtracting 12 from both sides yields:

Thus, the x-coordinate of the point where the two lines intersect is:

To find the y-value, we can use either function. Using the second function, we acquire:

(You will obtain the same result if you use the first function. Try it!)

Thus, the point of intersection is (-3, 0).

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

according to egenuity the answer is

step-by-step explanation:

d. 344.22