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Mathematics, 09.03.2021 23:40 montgomerykarloxc24x

How can (a+3)2=a2+6a+9 be derived from the polynomial identity (aβˆ’3)2=a2βˆ’6a+9? A. Add 12a to both sides of (aβˆ’3)2=a2βˆ’6a+9.
B. Add 6 to both sides of (aβˆ’3)2=a2βˆ’6a+9.
C. Multiply both sides of (aβˆ’3)2=a2βˆ’6a+9 by βˆ’1.
D. Substitute βˆ’a for a on both sides of (aβˆ’3)2=a2βˆ’6a+9.

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How can (a+3)2=a2+6a+9 be derived from the polynomial identity (aβˆ’3)2=a2βˆ’6a+9? A. Add 12a to both s...
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