Find two integers whose sum is -13 and product is 42

they are -6 and -7

Step-by-step explanation:

x+y=-13i

xy=42ii

from i, x=-13-y...iii

put iii in ii

y(-13-y) =42

-13y-y=42

-12y=42

y=42/-12

y= -3.5

put y= -3.5 in I

x-3.5=-13

x= -13+3.5

x= -9.5

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752