In 2010, the population of a city was 69,000. From 2010 to 2015, the population grew by 7.1%. From 2015 to 2020, it fell by 3%. How much did the population grow from 2010 to 2015, to the nearest 100 people?

4,899

Step-by-step explanation:

The computation is shown below:

Given that

In the year 2010, the population of the city was 69,000

From 2010 to 2015 the population would be grow by 7.1%

So, in the year 2015, the population is

= 69,000 + 69,000 × 7.1%

= 69,000 + 4,899

= 73,899

Now the growth would be

= 73,899 - 69,000

= 4,899

7

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)