What are the more appropriate measures of center and spread for this data set?

Select two choices: one for the center and one for the spread.

A. Better measure of center: the mean

B. Better measure of spread: the standard deviation

C. Better measure of center: the median

D. Better measure of spread: the interquartile range (IQR)

Median and IQR

Step-by-step explanation:

Out of 3 central tendencies, mean, median and mode, median is the better measure.

i) Mean is affected by extreme values

ii) Mean is not correct if more outliers are present

iii) Mean may not represent the nature of the data whether skewed right or left.

But median the middle entry is not affected by extreme items or outliers so median is better than mean,

For measure of spread, IQR is better since extreme items will show higher std deviation, and also some outliers mislead.  But IQR gives a good idea.

Step-by-step explanation:

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5

answer: 486in^2

step-by-step explanation: