You are the manager of a restaurant that delivers pizza to college dormitory rooms. You have just changed your delivery process in an effort to reduce the mean time between the order and completion of delivery from the current 21 minutes. A sample of 36 orders using the new delivery process yields a sample mean of 22.4 minutes and a sample standard deviation of 6 minutes. A.) Please compute the test statistic. Please round to four decimal places.
B.) Please determine the p-value. Please round to four decimal places.
C.) Using a 0.05 level of significance, please provide the critical value for the appropriate test. Please round to four decimal places.
D.) Using a 0.05 level of significance, is there evidence that the population mean delivery time has been reduced below the previous population mean value of 25 minutes?

1.4000 ;

0.0807 ;

1.69 ;

Fail to reject the Null

Step-by-step explanation:

Given :

μ = 21 minutes

x = 22.4 minutes

Sample size, n = 36

Standard deviation, s = 6

H0: μ ≥ 21

H1: μ < 21

Test statistic : (x - μ) ÷ s/sqrt(n)

Test statistic : (22.4 - 21) ÷ 6/sqrt(36)

Test statistic : 1.4 ÷ 1

Test statistic = 1.4000

Pvalue : Using the Test statistic value at α = 0.05 ; One - tail test = 0.0807

The t critical value using a critical value calculator ; DF = (n - 1) = 36 - 1 = 35 ; α = 0.05 = 1.69

Decision region :

Reject H0 if

|Test statistic| > |critical value|

1.4 < 1.69

Hence, we fail to reject H0

There isn't enough evidence they delivery time has been reduced below previous mean

it would not be increasing by nothing that i can see probably by 25 percent that is all i can sat\y for now if i have any thing else to say i will edit this.

step-by-step explanation: