A soft-drink machine is regulated so that the amount of drink dispensed is approximately normally distributed with known standard deviation, sigma. Given a random sample of n drinks and the sample mean, x-bar, you find a 90% confidence interval for the mean of all drinks dispensed by this machine. Then you calculate a 90% confidence interval (same confidence level) using a larger sample, for example (n 20) drinks. Also, you notice that the sample mean, x-bar, is the same for both samples. Required:
Was this a reasonable decision?

This is  a reasonable decision because the sample size has no effect on the 90% confidence interval

Step-by-step explanation:

90% confidence interval

larger sample size = 20

condition : sample mean ( x-bar ) is the same for both samples

This is  a reasonable decision because the sample size has no effect on the 90% confidence interval

from condition 1 :

Amount of drink dispensed is normally distributed with known standard deviation , given a random sample of n drinks and the sample mean at a confidence interval of 90%

for condition 2 :

sample size = 20

mean = 2.25 ( assumed value )

std = 0.15 ( assumed value )

Z = 1.645 ( Z-value )

determine the 90% confidence interval

= mean ± z

= 2.25 ± 1.645

= 2.25 ± 0.0335 = ( 2.2835 , 2.2165 )

parallel and congruent

step-by-step explanation:

the movement of translation is linear.   these have the same translation because you are using the same rule for each point of the triangle so you will see the same slope being used to get from a point on the triangle to its image.

same slope!   you should think parallel when you see those 2 word together (well unless it's the same line but it can't be because we are coming from different points here)

congruent! because each point is being moved the same distance.