A 26 ft. Ladder is placed against a building with the base of the ladder 8ft away from the building. What angle does the ladder make with the building?

θ = 13.3°

Step-by-step explanation:

Given that :

Height of ladder = 26 ft

Distance between base and wall of building = 6 feets

To obtain the angle θ ;

Using Pythagoras rule :

Sinθ = opposite / hypotenus

Opposite = 6feets

Hypotenus = 26 feets

Sinθ = 6 /26

Sinθ = 0.2307692

θ = sin^-1(0.2307692)

θ = 13.342363

θ = 13.3°

a=r

d=q

c=p

b=s

hope this !

where r the answers

step-by-step explanation: