Write the standard equation of a circle with
center (3,-2) and a radius of 6

could you reply to this with the question so i can ?

a reflection across the x-axis , followed by the by a reflection across the y-axis , and then a scale dilation of 0.5 .

answer: (-6,3)

step-by-step explanation:

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629