What is the solution to the system of equations?

y =1/3 x – 10

2x + y = 4

(–8, 6)
(–6, 16)
(6, –8)
(16, –6)

Y = 1/3x - 10
sub in 1/3x - 10 in for y in the other equation

2x + y = 4
2x + 1/3x - 10 = 4...multiply everything by 3 to get rid of factions
6x + x - 30 = 12
7x = 12 + 30
7x = 42
x = 42/7
x = 6

2x + y = 4
2(6) + y = 4
12 + y = 4
y = 4 - 12
y = - 8

solution is : (6,-8)

What’s your question.

I’m not sure about that