Find the least common denominator for the pair of rational numbers. x+1 X-5
_ ; _
2x^2-5x-3 2x +1

the LCD is a) (2x+1)(x-3)

Step-by-step explanation:

step 1.)

factorise: 2x²+1- 5x-3 becomes (2x+1)(x-3) when you factorise it and the 2x+1 stays (2x+1).

step 2.)

since 2x+1 are in both denominators you only write it once and don't forget to include x-3 as an LCD

therefore (2x+1)(x-3) is the LCD.

step-by-step explanation:

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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