Get your bearings A large container of ball bearings has mean diameter 2.5003 centimeters (cm). This is within the specifications for acceptance of the container by the purchaser. By chance, an inspector chooses 100 bearings from the container that have mcan diaineler 2.5009 cm. Because this is outside the specificd limits, the container is mistakenly rejected. The parameter is_=_
The statistic is _=_

Options:
A u/q looking thing (my phone doesn't have it)
x-bar
2.5003
2.5009​

your answers are

m=2.5003

and

x=2.5009

Step-by-step explanation:

hope this is what you are looking for

have a nice day ^_^

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2