A north-bound ocean liner is approaching Juneau at the rate of 60 km/h and is scheduled to reach the port at 8:21 am. A tugboat leaves Juneau at 7:57 am and heads west at the rate of 75 km/h. What is the smallest distance between the two boats? solve using optimization of distances (calculus)

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” iswhen n=4,we substitute 4 whetever we see n to get,we simplify to obtain,we further simplify to get,therefore the correct answer is c.

Answer: v= lwhstep by step explanation: length x width x heightl = 12kmw = 6kmh = 6km12 x 6 = 7272 x 6 = 432therefore your answer would be c) 432 km^3