Javon won Indianapolis 500 race in 2011 with an average speed of 170.265 miles per hour. What was his average speed to the nearest tenth of a mile per hour? How do you get the answer?

170.3 miles per hour

Step-by-step explanation:

Javon won Indianapolis 500 race in 2011 with an average speed of 170.265 miles per hour. What was his average speed to the nearest tenth of a mile per hour?

From the above question, we are asked to approximate to the nearest tenth of a mile.

The number that falls under the tenth of a mile, is the number that is immediately after the decimal.

Hence, for:

170.265 miles per hour:

2 is the number in the tenth place, the number after 2 is 6, it is a number that is higher than 5. So we add 1 to 2

Therefore,

170.265 miles per hour to the nearest tenth of a mile = 170.3 miles per hour.

nearest

step-by-step explanation:

b and c

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204