I have posted this same question 3 times now and i've tried working on it but I keep getting stuck. If someone can please help me that would be great thanks! What is the value of k such that (x^3−x2+kx+40)÷(x + 5) has a remainder of zero? Then, factor the polynomial completely.

-5k - 150

Step-by-step explanation:

i could be wrong

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)