Mathematics, 06.03.2021 01:20 22savage2017
Jesse and Benjamin are asked to factor 100x^2β100. Here are their solutions. Who is correct?
Jesse
100x^2β100=(10x)^2β10^2
=(10x-10)(10x+10)
=10(x-1)(10)(x+1)
=100(x-1)(x+1)
Benjamin
100x^2-100=100(x^2-1)
=100(x-1)(x+1)
Answers: 3
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Jesse and Benjamin are asked to factor 100x^2β100. Here are their solutions. Who is correct?
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