Given f(x)=2x^3+kx-9f(x)=2x 3 +kx−9, and the remainder when f(x) is divided by x−2 is 23, then what is the value of k?

Given:

The function is

The remainder when f(x) is divided by x−2 is 23.

To find:

The value of k.

Solution:

According to the remainder theorem, if a polynomial P(x) is divided by (x-c), then the remainder is P(c).

It is given that, the remainder when f(x) is divided by x−2 is 23. By using remainder theorem, we get

      ...(i)

Put x=2, to find the value of f(2).

         ...(ii)

Using (i) and (ii), we get

Therefore, the value of k is 8.

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