You and your friend are selling tickets to a charity event. You sell two adult tickets and six student tickets for $12. Your friend sells for adult tickets and 15 student tickets for $27. What is the cost of each ticket?

Your friend sells "for"adult tickets and 15 student tickets for $27, I think you meant "four" adult tickets and 15 student tickets for $27.

Adult ticket costs $3

Student ticket cost $1

Step-by-step explanation:

Let the cost adult ticket be represented as X

And cost student tickets be represented as y

Such that two adult tickets and six student tickets for $12 would be expressed as

2x+6y=12

And

four adult tickets and 15 student tickets for $27.

4x+15y=27

The equations to solve becomes

2x+6y=12equation 1

4x+15y=27equation2

Solving

Multiply equation 1by 4 and equation 2by 2

8x+24y=48---equation 3

8x+30y=54equation4

Subtracting equation 3from equation 4

6y=6

Y=6/6

Y=1

Putting the value of y=1in equation 1and solving for x becomes

2x+6y=12

2x+6x1=12

2x=12-6

2x=6

X=6/2=3

Adult ticket costs $3

Student ticket cost $1

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.