A scientist mixes water (containing no salt) with a solution that contains 35% salt. She wants to obtain 105 ounces of a mixture that is 15% salt. How many ounces of water and how many ounces of the 35% salt solution should she use?

60 oz of water to add

45 oz of 35% salt solution should be used

Step-by-step explanation:

Let x = amt no. ounces in the first solution

and  105 - x = amt no. of ounces in the second solution

Ist solution contains 0% salt

2nd solution contains .35(105 - x) salt

.15(105= amt of salt in mix

So.

amt of salt in 1st solution + amt of salt in 2nd solution = amt of salt in the mix

0 + .35(105 - x) = .15(105)

Let's get rid of the fractions by multipying thru the equation by 100

35(105 - x) = 15(105)

3675 - 35x = 1575

-35x = -2100

x = 60 oz of water to add

105 - 60 = 45 oz of 35% salt solution should be used

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

1.true 2.false? ? i think. .

step-by-step explanation: