PLEASE HELP!! I'LL GIVE 20 POINTS TO WHOEVER CAN ANSWER CORRECTLY! Quadratic functions g(x) and h(x) are graphed on the same coordinate grid. The vertex of the graph of h(x) is 12 units above the vertex of the graph of g(x) .

Which pair of functions could have been used to create the graphs of g(x) and h(x)?

h(x)=(x+12)2 and ​g(x)=x2​

h(x)=(x−12)2 and ​g(x)=x2

h(x)=x2+12 and ​g(x)=x2​

h(x)=x2−12 and g(x)=x2

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

21

jk it's 20

step-by-step explanation:

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)