A rectangle has height and width changing in such a way that the area remains constant 2 square feet. At the instant the height is 2 feet, the height is changing at a rate of 6 feet/minute. Find the rate of change of the width (in feet/min) at that instant.

ft/min is the rate of changing of width

Step-by-step explanation:

Given -

The area always remain constant i.2 2 square feet.

Height of the rectangle = 2 feet

Rate of changing of height = 6 feet per minute

Since area is constant

2 sq ft = (2 * 6) ft/min * 1 * x ft/min

x = ft/min

37

step-by-step explanation:

hreryryrranswer:

step-by-step explanation: