A sandwich shop offers 3 different kinds of bread, 4 different kinds of meat, and 6 different toppings. How many different sandwiches with one bread, one meat, and one topping are possible?​

yeah

Step-by-step explanation:

0

Your second impression was "right"; the answer is 36 in one restricted interpretation of the problem, in which a sandwich has precisely one type of bread, one type of meat, and one type of cheese.

The largest possible interpretation is that a sandwich consists of a top bread, 1 to 3 types of meat, 1 to 3 types of cheese, and a bottom bread which could be different from the top slice of bread (but two sandwiches are considered the same if the only difference is turning one upside down). The answer to that problem involves, for example, seven possible combination of meats, and is

(42)bread⋅(23−1)meat⋅(23−1)cheese=6⋅7⋅7=594

If you must use the same type of bread top and bottom the answer is

(41)bread⋅(23−1)meat⋅(23−1)cheese=4⋅7⋅7=396

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh

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step-by-step explanation: