Write an equation of a linear function with slope −2 that passes through the point (4,−5).

y=-2x+3

Step-by-step explanation:

y-y1=m(x-x1)

y-(-5)=-2(x-4)

y+5=-2x+8

y=-2x+8-5

y=-2x+3

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: