HELP THIS WAS DUE THREE DAYS AGO

Step-by-step explanation:

2. 2c(7c + 1)

3. stays as is

4. 2x^3y^4(4 - 11x^2y^2)

5. ab(10ab + 9b - a)

6. 3m^2(7m^4n^2+2m^2n+5)

7. (a - 8)(a + 8)

8. (y - 17)(y + 17)

9. stays as is

10. (1 - 5n)(1 + 5n)

11. (4x - 7y)(4x + 7y)

12. (w^2 - 10)(w^2 + 10)

13. (c - 9d)(c + 9d)

14. (14a - b)(14a + b)

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2