Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40°. Building A is 120 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet? Building A; it is around 100.69 feet taller than building B
Building A; it is around 50.34 feet taller than building B
Building B; it is around 100.69 feet taller than building A
Building B; it is around 50.34 feet taller than building A

B. Building A; it is around 50.34 feet taller than building B.

Step-by-step explanation:

Let the height of building A be represented by x, and that of B by y. Applying the required trigonometric function, we have;

Tan θ =

Tan 40 =

x = 120 x Tan 40

  = 120 x 0.8391

x = 100.692

Thus, the height of building A is 100.69 feet.

The height of building B can be determined by;

Tan θ =

Tan 40 =

y = 60 x Tan 40

  = 60 x 0.8391

y = 50.346

Thus, the height of building B is 50.35 feet.

Therefore it can be observed that Building A is about 50.34 feet taller than building B.

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)