A rocket is launched from the top of a 30 foot cliff with an initial velocity of 160 feet per second. The height, h, of the rocket after t seconds is given by the equation h = - 16t2 + 160t + 30. How long after the rocket is launched will it be 10 feet from the ground?​

for b its (t) and c its (d)

step-by-step explanation:

22 and 22

step-by-step explanation:

10 plus 12 equals 22.

12 plus 10 also equals 22 because regardless of what order they're in, they're gonna equal the same thing.

50.6

step-by-step explanation:

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50