Y=-1|x-2|+1 how to solve

if    x ≥ 2, then y = x - 1

if    x < 2, then y = -x + 3

Step-by-step explanation:

y = 1* |x - 2|  +  1

y = |x-2| + 1

*** The rule on absolute value: |a| =a, if a ≥ 0; |a| = -a, if a < 0

If       x-2 ≥ 0,   then |x-2| = x-2, so y = (x - 2) + 1 = x - 1; y = x - 1

So   if    x ≥ 2, then y = x - 1

If      x-2 < 0,    then |x-2| = -(x-2) = -x + 2, so y =  {-x + 2} + 1 = -x + 3; y = -x + 3

So   if    x < 2, then y = -x + 3

image for option 4

step-by-step explanation:

i just know the internet