The perimeter of a rectangle is 86. The length of the rectangle is one more than twice the width. Determine the length and width of the rectangle.

There are two equation of the system

(1) The perimeter

    2(w + l) = p

    2(w + l) = 86

(2) The length and the width

     2w = l + 2

From the second equation

2w = l + 2

l + 2 = 2w

l = 2w - 2

Subtitute l with 2w - 2 in the first equation to find the width

2(w + l) = 86

2(w + 2w - 2) = 86

2(3w - 2) = 86

6w - 4 = 86

6w = 90

w = 15

Now, find the length by subtituting w with 15

l = 2w - 2

l = 2(15) - 2

l = 30 - 2

l = 28

The dimension of the rectangle

length = 28 cm

width = 15 cm

555.99.

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