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![\mathsf{\dfrac{\Delta f}{h}=\dfrac{f(x+h)-f(x)}{h}}\\\\\\ =\mathsf{\dfrac{\big[2(x+h)^2-2(x+h)+5\big]-(2x^2-2x+5)}{h}}\\\\\\ =\mathsf{\dfrac{\big[2(x^2+2xh+h^2)-2x-2h+5\big]-2x^2+2x-5}{h}}\\\\\\ =\mathsf{\dfrac{\big[\;\diagup\!\!\!\!\!\!\! 2x^2+4xh+2h^2-\diagdown\!\!\!\!\!\! 2x-2h+\diagup\!\!\!\!\diagup\!\!\!\! 5\,\big]-\,\diagup\!\!\!\!\!\!\! 2x^2+\diagdown\!\!\!\!\!\! 2x-\diagup\!\!\!\!\diagup\!\!\!\! 5\;}{h}}](/tpl/images/0474/0679/e54b3.png)
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F(x) =2x^2-2x+5 evaluate f(x+h) - f(x)/h...
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