F(x)=3x(x^2+4x-5) evaluate f(-2)​

f(-2) = 54

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

f(x) = 3x(x² + 4x - 5)

f(-2) is x = -2

Step 2: Evaluate

Substitute in x  [Function]:                                                                             f(-2) = 3(-2)[(-2)² + 4(-2) - 5][Brackets] Evaluate exponents:                                                                     f(-2) = 3(-2)[4 + 4(-2) - 5][Brackets] Multiply:                                                                                         f(-2) = 3(-2)[4 - 8 - 5][Brackets] Subtract:                                                                                        f(-2) = 3(-2)[-4 - 5][Brackets] Subtract:                                                                                        f(-2) = 3(-2)(-9)Multiply:                                                                                                           f(-2) = -6(-9)Multiply:                                                                                                           f(-2) = 54

Hello!

the answer is:

the answer is:

why?

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!