Group A rented and filled 3 vans and 6 buses with 204 students. Group B rented and filled 1 van and 3 buses with 97 students. Every van had the same number of students in it as did the buses. Select which TWO equations can be used to represent this situation.

A. v + b = 107
B. 3v + 6b = 204
C. 3v + 3b = 97
D. v + 3b = 97
E. v + 6b = 204
F. 2v + 9b = 107

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

step-by-step explanation:

if you want to separate 54 into 6 individual tiers then you need to divide if you want to separate 54 into 6 individual tiers then you need to divide 6 and 54.

if you divide 9 by 6 you will get 54.

- hope i .

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)