A sequence of 8 numbers is formed such that each term is the product of the two previous terms. Given to terms in the sequence, find the rest of the terms.

Ok so its 1/3, 3, 1, 3, 3, 9, 27, 243

Step-by-step explanation:

So you need 3*3 preceding the 9 because that's the only thing that equals nine when multiplied. And you need ones before that, but you can't just have 1*1*1, cause that would go on forever. So you need a fraction times something that will give you one, and it has to be three if you want to with the rest of the problem.  

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step-by-step explanation:

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