A city bus collected $1,140 in fares on a given day. The regular fare is $1.50, and the reduced fare is $0.75. If 1,042 total fares were paid, which system of linear equations can be used to find x, the number of regular fares paid, and y, the number of reduced fares paid?

x + y = 1042

1.50x + 0.75y = 1140

Step-by-step explanation:

If there was a total of 1,042 fares paid then x + y would be equal to that because x is the number of regular fares paid and y is the number of reduced fares paid.

If there was a total of $1,140 made from the fares then we can use 1.50x + 0.75y. We put the 1.5 in front of the x because each fare paid costs $1.50, same with Y each reduced fare paid is $0.75. So both of those need to be added up to get $1,140.

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube