Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If AC=6AC=6 and DC=4,DC=4, what is the length of \overline{BC} BC in simplest radical form? (Note: the figure is not drawn to scale.)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

hi! i think the answer is 1/2 : )

sorry i just need to anwers this to get points

step-by-step explanation: