what is the equation in standard form of the line that passes through the point (2,32) and has a slope of -0.8

y=0.8x+30.4

Step-by-step explanation:

You know that the slop is -0.8 and you know one point on the line which is (2,32). That means, you have to use the point slope formula which is y-y1=m(x-x1) where m is the slope. Plug the point and the slope into the formula to get y-32=-0.8(x-2). Simplify this to get y-32=-0.8x-1.6. Isolate the y by adding 32 in each side. This will make the equation y=0.8x+30.4. Therefore the equation is y=0.8x+30.4.

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