What is the equation of the line that is parallel to y =1/5x+4 and that passes through (5,-4)?
y=-5x-29
y=-5x+21
y=1/5x-4
y=1/5x-5

y=(1/5)x-5

Step-by-step explanation:

The given equation is

y=(1/5)x+4

This is of the form

y=mx+b

which is called the slope-intercept form because

m is the slope

b is the y intercept.

In this case,

m=1/5

b=4

you can see from the chart that this matches the red line.

If two lines are parallel, they must have the same slope. So we know that the slope of the desired line is 1/5.  So, now we know that

y=(1/5)x+b

Since the line must go through the point (5,-4), we have

-4=(1/5)(5)+b

-4=1+b

b=-5

So, the desired line is

y=(1/5)x-5