There is a bag filled with 4 blue, 3 red and 5 green marbles. A marble is taken at random from the bag, the colour is noted and then it is not replaced.
Another marble is taken at random.
What is the probability of getting exactly 1 green?

Step-by-step explanation:

P(g=1) is equal to

1-P(g=0)-P(g=2)

P(g=0)=(7/12)(6/11)

P(g=2)=(5/12)(4/11) so

P(g=1)=1-(42/132)-(20/132)

P(g=1)=(132-42-20)/132

P(g=1)=70/132

P(g=1)=35/66

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation:

4.08%

step-by-step explanation: