What is the distance from the origin to the graph of 3x-y+1=0

the shortest distance will be the perpendicular distance from the origin to the line y=3x-10

the equation of this line will have the negative reciprocal for its slope

y=mx+b

y=(-1/3)x+b

this line goes through the origin, (0,0)

0=(-1/3)(0)+b

0=0+b

b=0

the equation of this line is y=(-1/3)x

using this equation and y=3x-10, find the point of intersection

(-1/3)x=3x-10

3x+(1/3)x=10

(10/3)x=10

x=3, so y=3*3-10, y=9-10, y=-1

the point of intersection is (3,-1)

use the points (0,0) and (3,-1) and the distance formula to find the perpendicular distance from the origin to the point (3,-1)

√([3-0)]2+[-1-0]2)

√(32+[-1]2)

√(9+1)

√10 is the shortest distance from the origin to the line y=3x-10

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

step-by-step explanation: