A car purchased for $20,000 depreciates annually at a rate of 8%. What will be the approximate value of the car in the 10th year?

$4000

Step-by-step explanation:

20000x0.08=1600

1600x10=16000

20000-16000=4000

$8687.76

Step-by-step explanation:

100-8=92

20,000*0.92=18400 (This is after one year)

20,000*0.92^10= 8687.7690 (After 10 years)

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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