How do i graph y−3=1/2(x+3) on this graph? : c

i will be giving a to anyone who me with this! ; w;

You must first get the equation in slope-intercept form. y-3=1/2(x+3) First, distribute the 1/2 to the x and 3 Your equation should look like this: y-3=1/2x+1.5 Next, add the three to both sides of the equation. Your equation should look like this: y=1/2x+4.5 To graph, you must determine your y-intercept and slope values. 1/2 is the slope value and 4.5 is the y-intercept. First plot the y-intercept at the point (0, 4.5). Next, go down one whole unit and then left 2 whole units. This point should be (-2, 3.5). Repeat this process until the equation's line extends all the way to the ends of the graph. To plot the points going up, go up one whole unit and then right two whole units. This point should be (2, 5.5). Good luck!! Hope this helped :3

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !